/*************************************************************************** machine.c Same Epos board as usual(theglobp,beastf,street heat), see theglobp.c for hardware documentation. This is fairly easy to decrypt since it has consecutive bytes with the same algorithym. There are 4 different algorithyms. One consists almost entirely of text, one contains the majority of code and the remaining 2 are not used much and are therefore the most difficult. It is however difficult to decrypt to rom. The data for the coin sound is actually program code in a different phase. You need to move the sound tables and add a rom to get it to run without the daughterboard. acitya contains a bug with the insurance in blackjack. It's impossible to collect, so it's likely that acitya is earlier than bwcasino. I don't think this game is a gambling game. For one thing there's no real output hardware on a pacman board and the epos daughterboard doesn't contain any either. David Widel d_widel@hotmail.com ***************************************************************************/ #include "driver.h" #include "includes/pacman.h" static INT8 counter=0; static void acitya_decrypt_rom_8(void) { int oldbyte,inverted_oldbyte,newbyte; int mem; UINT8 *RAM; RAM = memory_region(REGION_CPU1); for (mem=0;mem<0x4000;mem++) { oldbyte = RAM[mem]; inverted_oldbyte = ~oldbyte; /* Note: D2 is inverted and connected to D1, D5 is inverted and connected to D0. The other six data bits are converted by a PAL10H8 driven by the counter. */ newbyte = 0; /* Direct inversion */ newbyte = (inverted_oldbyte & 0x80) >> 2; newbyte |= (oldbyte & 0x40) >> 0; newbyte |= (inverted_oldbyte & 0x20) >> 5; newbyte |= (inverted_oldbyte & 0x10) >> 1; newbyte |= (oldbyte & 0x08) << 1; newbyte |= (inverted_oldbyte & 0x04) >> 1; newbyte |= (oldbyte & 0x02) << 6; newbyte |= (inverted_oldbyte & 0x01) << 2; RAM[mem + 0x10000] = newbyte; } return; } static void acitya_decrypt_rom_9(void) { int oldbyte,inverted_oldbyte,newbyte; int mem; UINT8 *RAM; RAM = memory_region(REGION_CPU1); for (mem=0;mem<0x4000;mem++) { oldbyte = RAM[mem]; inverted_oldbyte = ~oldbyte; /* Note: D2 is inverted and connected to D1, D5 is inverted and connected to D0. The other six data bits are converted by a PAL10H8 driven by the counter. */ newbyte = 0; /* Direct inversion */ newbyte = (inverted_oldbyte & 0x80) >> 0; newbyte |= (oldbyte & 0x40) >> 0; newbyte |= (inverted_oldbyte & 0x20) >> 5; newbyte |= (oldbyte & 0x10) >> 1; newbyte |= (oldbyte & 0x08) << 1; newbyte |= (inverted_oldbyte & 0x04) >> 1; newbyte |= (inverted_oldbyte & 0x02) << 4; newbyte |= (inverted_oldbyte & 0x01) << 2; RAM[mem + 0x14000] = newbyte; } return; } static void acitya_decrypt_rom_A(void) { int oldbyte,inverted_oldbyte,newbyte; int mem; UINT8 *RAM; RAM = memory_region(REGION_CPU1); for (mem=0;mem<0x4000;mem++) { oldbyte = RAM[mem]; inverted_oldbyte = ~oldbyte; /* Note: D2 is inverted and connected to D1, D5 is inverted and connected to D0. The other six data bits are converted by a PAL10H8 driven by the counter. */ newbyte = 0; newbyte = (inverted_oldbyte & 0x80) >> 2; newbyte |= (inverted_oldbyte & 0x40) >> 2; newbyte |= (inverted_oldbyte & 0x20) >> 5; newbyte |= (inverted_oldbyte & 0x10) >> 1; newbyte |= (inverted_oldbyte & 0x08) >> 1; newbyte |= (inverted_oldbyte & 0x04) >> 1; newbyte |= (oldbyte & 0x02) << 6; newbyte |= (oldbyte & 0x01) << 6; RAM[mem + 0x18000] = newbyte; } return; } static void acitya_decrypt_rom_B(void) { int oldbyte,inverted_oldbyte,newbyte; int mem; UINT8 *RAM; RAM = memory_region(REGION_CPU1); for (mem=0;mem<0x4000;mem++) { oldbyte = RAM[mem]; inverted_oldbyte = ~oldbyte; /* Note: D2 is inverted and connected to D1, D5 is inverted and connected to D0. The other six data bits are converted by a PAL10H8 driven by the counter. */ newbyte = 0; /* Direct inversion */ newbyte = (inverted_oldbyte & 0x80) >> 0; newbyte |= (inverted_oldbyte & 0x40) >> 2; newbyte |= (inverted_oldbyte & 0x20) >> 5; newbyte |= (oldbyte & 0x10) >> 1; newbyte |= (inverted_oldbyte & 0x08) >> 1; newbyte |= (inverted_oldbyte & 0x04) >> 1; newbyte |= (inverted_oldbyte & 0x02) << 4; newbyte |= (oldbyte & 0x01) << 6; RAM[mem + 0x1C000] = newbyte; } return; } READ8_HANDLER( acitya_decrypt_rom ) { if (offset & 0x01) { counter = counter - 1; if (counter < 0) counter = 0x0F; } else { counter = (counter + 1) & 0x0F; } switch(counter) { case 0x08: memory_set_bank (1, 0); break; case 0x09: memory_set_bank (1, 1); break; case 0x0A: memory_set_bank (1, 2); break; case 0x0B: memory_set_bank (1, 3); break; default: logerror("Invalid counter = %02X\n",counter); break; } return 0; } MACHINE_RESET( acitya ) { UINT8 *RAM = memory_region(REGION_CPU1); /* While the PAL supports up to 16 decryption methods, only four are actually used in the PAL. Therefore, we'll take a little memory overhead and decrypt the ROMs using each method in advance. */ acitya_decrypt_rom_8(); acitya_decrypt_rom_9(); acitya_decrypt_rom_A(); acitya_decrypt_rom_B(); /* The initial state of the counter is 0x0B */ counter = 0x0B; memory_configure_bank(1, 0, 4, &RAM[0x10000], 0x4000); memory_set_bank(1, 3); state_save_register_global(counter); }