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+// license:BSD-3-Clause
+// copyright-holders:David Widel
+/***************************************************************************
+
+ machine.c
+
+Same Epos board as usual(theglobp,beastf,street heat), see theglobp.c for hardware documentation. This is fairly easy to decrypt since it has consecutive bytes with the same algorithym. There are 4 different algorithyms. One consists almost entirely of text, one contains the majority of code and the remaining 2 are not used much and are therefore the most difficult. It is however difficult to decrypt to rom. The data for the coin sound is actually program code in a different phase. You need to move the sound tables and add a rom to get it to run without the daughterboard.
+
+acitya contains a bug with the insurance in blackjack. It's impossible to collect, so it's likely that acitya is earlier than bwcasino.
+
+I don't think this game is a gambling game. For one thing there's no real output hardware on a pacman board and the epos daughterboard doesn't contain any either.
+
+David Widel d_widel@hotmail.com
+
+***************************************************************************/
+
+#include "emu.h"
+#include "includes/pacman.h"
+
+
+void pacman_state::acitya_decrypt_rom_8()
+{
+ int oldbyte,inverted_oldbyte,newbyte;
+ int mem;
+ UINT8 *RAM;
+
+ RAM = memregion("maincpu")->base();
+
+
+ for (mem=0;mem<0x4000;mem++)
+ {
+ oldbyte = RAM[mem];
+ inverted_oldbyte = ~oldbyte;
+
+ /* Note: D2 is inverted and connected to D1, D5 is inverted and
+ connected to D0. The other six data bits are converted by a
+ PAL10H8 driven by the counter. */
+
+ /* Direct inversion */
+ newbyte = (inverted_oldbyte & 0x80) >> 2;
+ newbyte |= (oldbyte & 0x40) >> 0;
+ newbyte |= (inverted_oldbyte & 0x20) >> 5;
+ newbyte |= (inverted_oldbyte & 0x10) >> 1;
+ newbyte |= (oldbyte & 0x08) << 1;
+ newbyte |= (inverted_oldbyte & 0x04) >> 1;
+ newbyte |= (oldbyte & 0x02) << 6;
+ newbyte |= (inverted_oldbyte & 0x01) << 2;
+
+ RAM[mem + 0x10000] = newbyte;
+ }
+
+ return;
+}
+
+
+void pacman_state::acitya_decrypt_rom_9()
+{
+ int oldbyte,inverted_oldbyte,newbyte;
+ int mem;
+ UINT8 *RAM;
+
+ RAM = memregion("maincpu")->base();
+
+ for (mem=0;mem<0x4000;mem++)
+ {
+ oldbyte = RAM[mem];
+ inverted_oldbyte = ~oldbyte;
+
+ /* Note: D2 is inverted and connected to D1, D5 is inverted and
+ connected to D0. The other six data bits are converted by a
+ PAL10H8 driven by the counter. */
+
+ /* Direct inversion */
+ newbyte = (inverted_oldbyte & 0x80) >> 0;
+ newbyte |= (oldbyte & 0x40) >> 0;
+ newbyte |= (inverted_oldbyte & 0x20) >> 5;
+ newbyte |= (oldbyte & 0x10) >> 1;
+ newbyte |= (oldbyte & 0x08) << 1;
+ newbyte |= (inverted_oldbyte & 0x04) >> 1;
+ newbyte |= (inverted_oldbyte & 0x02) << 4;
+ newbyte |= (inverted_oldbyte & 0x01) << 2;
+ RAM[mem + 0x14000] = newbyte;
+ }
+
+ return;
+}
+
+void pacman_state::acitya_decrypt_rom_A()
+{
+ int oldbyte,inverted_oldbyte,newbyte;
+ int mem;
+ UINT8 *RAM;
+
+ RAM = memregion("maincpu")->base();
+
+ for (mem=0;mem<0x4000;mem++)
+ {
+ oldbyte = RAM[mem];
+ inverted_oldbyte = ~oldbyte;
+
+ /* Note: D2 is inverted and connected to D1, D5 is inverted and
+ connected to D0. The other six data bits are converted by a
+ PAL10H8 driven by the counter. */
+
+ newbyte = (inverted_oldbyte & 0x80) >> 2;
+ newbyte |= (inverted_oldbyte & 0x40) >> 2;
+ newbyte |= (inverted_oldbyte & 0x20) >> 5;
+ newbyte |= (inverted_oldbyte & 0x10) >> 1;
+
+ newbyte |= (inverted_oldbyte & 0x08) >> 1;
+ newbyte |= (inverted_oldbyte & 0x04) >> 1;
+ newbyte |= (oldbyte & 0x02) << 6;
+ newbyte |= (oldbyte & 0x01) << 6;
+ RAM[mem + 0x18000] = newbyte;
+ }
+
+ return;
+}
+
+void pacman_state::acitya_decrypt_rom_B()
+{
+ int oldbyte,inverted_oldbyte,newbyte;
+ int mem;
+ UINT8 *RAM;
+
+ RAM = memregion("maincpu")->base();
+
+ for (mem=0;mem<0x4000;mem++)
+ {
+ oldbyte = RAM[mem];
+ inverted_oldbyte = ~oldbyte;
+
+ /* Note: D2 is inverted and connected to D1, D5 is inverted and
+ connected to D0. The other six data bits are converted by a
+ PAL10H8 driven by the counter. */
+
+ /* Direct inversion */
+ newbyte = (inverted_oldbyte & 0x80) >> 0;
+ newbyte |= (inverted_oldbyte & 0x40) >> 2;
+ newbyte |= (inverted_oldbyte & 0x20) >> 5;
+ newbyte |= (oldbyte & 0x10) >> 1;
+ newbyte |= (inverted_oldbyte & 0x08) >> 1;
+ newbyte |= (inverted_oldbyte & 0x04) >> 1;
+ newbyte |= (inverted_oldbyte & 0x02) << 4;
+ newbyte |= (oldbyte & 0x01) << 6;
+
+
+ RAM[mem + 0x1C000] = newbyte;
+ }
+
+ return;
+}
+
+
+READ8_MEMBER(pacman_state::acitya_decrypt_rom )
+{
+ if (offset & 0x01)
+ {
+ m_counter = (m_counter - 1) & 0x0F;
+ }
+ else
+ {
+ m_counter = (m_counter + 1) & 0x0F;
+ }
+
+ switch(m_counter)
+ {
+ case 0x08: membank ("bank1")->set_entry (0); break;
+ case 0x09: membank ("bank1")->set_entry (1); break;
+ case 0x0A: membank ("bank1")->set_entry (2); break;
+ case 0x0B: membank ("bank1")->set_entry (3); break;
+ default:
+ logerror("Invalid counter = %02X\n",m_counter);
+ break;
+ }
+
+ return 0;
+}
+
+
+MACHINE_START_MEMBER(pacman_state,acitya)
+{
+ UINT8 *RAM = memregion("maincpu")->base();
+
+ /* While the PAL supports up to 16 decryption methods, only four
+ are actually used in the PAL. Therefore, we'll take a little
+ memory overhead and decrypt the ROMs using each method in advance. */
+ acitya_decrypt_rom_8();
+ acitya_decrypt_rom_9();
+ acitya_decrypt_rom_A();
+ acitya_decrypt_rom_B();
+
+ membank("bank1")->configure_entries(0, 4, &RAM[0x10000], 0x4000);
+
+ save_item(NAME(m_counter));
+}
+
+
+MACHINE_RESET_MEMBER(pacman_state,acitya)
+{
+ /* The initial state of the counter is 0x0B */
+ m_counter = 0x0B;
+ membank("bank1")->set_entry(3);
+}